Physics Forces Question with mass

AI Thread Summary
To determine the acceleration of a 6.0 kg mass acted upon by forces of 3.0 N and 1.0 N, it is essential to consider both forces rather than neglecting the 1.0 N force. The net force should be calculated using vector addition, as the forces may not be aligned at right angles. The 3.0 N force cannot be treated as the hypotenuse without incorporating the 1.0 N force, which contributes to the overall acceleration. A recommended approach is to resolve each force into its components along two perpendicular directions and then sum these components to find the resultant force. Properly accounting for all forces is crucial for accurate calculations in physics problems.
Hannahj1
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Homework Statement


A force of 3.0 N and 1.0 N act on a 6.0 kg mass as shown. What is the acceleration of the 6.0 kg mass?

Homework Equations


Fnet = ma

The Attempt at a Solution


I did 3N as fnet so fnet=ma, 3=6a and solved for a
i was just wondering if what i did was right and if i need to incorporate the 1N in any way? Thank you
 

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    Screen Shot 2015-08-10 at 12.09.34 AM.png
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Hi, Hannahj1.

Can you give a reason for neglecting the 1.0 N force when finding the net force?
 
TSny said:
Hi, Hannahj1.

Can you give a reason for neglecting the 1.0 N force when finding the net force?

When you find the net force it is usually the hypotenuse of the x and y components and here you're already given the hypotenuse (the 3N)
 
Yes, you do need to incorporate the 1N. Vector addition is necessary in this problem, as both forces have components that contribute to the acceleration of the block. You cannot ignore the 1N.
 
Hannahj1 said:
When you find the net force it is usually the hypotenuse of the x and y components and here you're already given the hypotenuse (the 3N)
That's because you are used to being given problems in which the applied forces are at right angles to each other, so the resultant is the hypotenuse.
But in general, as here, the applied forces can be at any angle to each other. The 3N line is not the hypotenuse of any triangle of interest.

A standard technique is to pick a pair of directions at right angles (vertical and horizontal in the screen shot would be convenient) and resolve each applied force into components in those two directions. Then you can add the components in each direction separately, and finally figure out what the resultant of those two forces is. Here, at last, you will be looking for the hypotenuse.
Do you know how to resolve a force into its components?
 
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