Physics Graph question -- Pushing a block on a frictionless surface

AI Thread Summary
The discussion centers on calculating the work done on a 7.20 kg block moving on a frictionless surface due to a varying force along the x-axis. The total work done as the block moves from the origin to 8.0 m is determined to be 33 J by calculating the area under the force vs. position graph in segments. For part B, the user seeks clarification on how to find the block's velocity at 8.0 m using the work-energy theorem. The work-energy theorem relates the work done on an object to its change in kinetic energy, suggesting that the user's understanding of this concept is crucial for solving the problem. The conversation emphasizes the importance of mastering work-energy relationships in physics.
Bdb1331
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The diagram shows how a force along the x-axis varies with location. A block of mass 7.20 kg moves along the x-axis on a horizontal frictionless surface, influenced by this force. (Graph is attached)
A) How much work is done by the force as the block moves from the origin to 8.0 m?

B) If the block has a velocity of 3.80 m/s at the origin, what is its velocity at 8.0 m?

For part A, I worked out the work to be 33 J by finding the area under the curve...
in the first two seconds

W = F(avg)d
W = [(2 + 8) / 2](2 - 0)
W = 10 J

from 2 to 4 seconds

W = [(8 + 4)/2] (4 - 2)
W = 12 J

from 4 to 6 s

W = 4(6 - 4)
W = 8 J

from 6 to 8 s

W = [(4 + -1)/2](8 - 6)
W = 3 J

Total work

W = 10 + 12 + 8 + 3
W = 33 J

But I am sort of lost when it comes to B)
 

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Are you familiar with work-energy relationships?
 
PhanthomJay said:
Are you familiar with work-energy relationships?
Sorta, but not exactly confident in my skills
 
Bdb1331 said:
Sorta, but not exactly confident in my skills
Well, just try using the work - energy theorem. What does that theorem say?
 
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