Physics Help: Lifting a 200 lb Beam w/ Unequal Weight

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To lift a 200 lb beam that is 20 feet long with one man bearing 50% more weight, the stronger man should carry 120 lbs while the weaker man carries 80 lbs. To achieve this balance, the stronger man needs to position himself closer to the heavier end of the beam. The calculations involve determining the appropriate distances from each end of the beam based on their respective weights. The discussion emphasizes the importance of understanding torque and balance in this scenario. The problem can be solved with basic physics principles regarding weight distribution.
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Not sure about this one, any help?

Two men want to carry a wooden beam weighing 200 lbs which is 20 feet long. Both men are equal height however one is stronger than the other and wishes to bear 50% more the weight. How far from the end of the beam should both of the men be to make this possible?
 
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That is a very easy problem. Do you really have no idea how to start? Let's see what you think first.
 
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