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For some reason I can’t solve this:

10. [PSE6 1.P.039.] One cubic meter (1.00 m3) of aluminum has a mass of 2.70 103 kg, and 1.00 m3 of iron has a mass of 7.86 103 kg. Find the radius of a solid aluminum sphere that will balance a solid iron sphere of radius 3.10 cm on an equal-arm balance.

I keep getting [tex] r =(\frac{2.7*3.1^3}{7.86} )^{1/3} [/tex]

10. [PSE6 1.P.039.] One cubic meter (1.00 m3) of aluminum has a mass of 2.70 103 kg, and 1.00 m3 of iron has a mass of 7.86 103 kg. Find the radius of a solid aluminum sphere that will balance a solid iron sphere of radius 3.10 cm on an equal-arm balance.

I keep getting [tex] r =(\frac{2.7*3.1^3}{7.86} )^{1/3} [/tex]

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