Physics problem involving gravity?

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To determine the distance from the center of the Earth where the gravitational force from Earth is twice that from the Moon, the gravitational forces acting on the spaceship must be compared. The relevant formula is F = Gm1m2/r^2, where m1 is the mass of the Earth and m2 is the mass of the spaceship. The mass of the spaceship is not needed for the ratio since it cancels out in the calculations. The focus should be on the gravitational forces exerted by both celestial bodies on the spaceship. Understanding this comparison is crucial for solving the problem accurately.
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A spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon.

At what distance from the center of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon?

r = ? m

I'm thinking of using the F = Gm1m2/r^2 with G being the gravitational constant and m1 being the mass of the earth, and m2 being the mass of the moon. but i don't know why they say "spaceship of mass m" or if that's even the proper formula to use?
 
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It's nothing. please go on.
 
what does that mean?
 
Don't consider the mass of spaceship.
 
what do i use as the force (F) in the formula I stated in order to isolate radius (r) and solve for it?
 
At what distance from the center of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon?

the force due to Earth and the force due to the Moon, what do they act on?
 
no clue what you are asking
 
the force act on spaceship,
F_E=Gm1m/r^2
and?
 
bkell27 said:
I'm thinking of using the F = Gm1m2/r^2 with G being the gravitational constant and m1 being the mass of the earth, and m2 being the mass of the moon. but i don't know why they say "spaceship of mass m" or if that's even the proper formula to use?
You need to compare the gravitational forces acting on the spaceship, not the the gravitational force between Earth and moon.
 
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