Physics Problem: Work and Force on a Skier Coasting Uphill with Friction

AI Thread Summary
The discussion revolves around a physics problem involving a skier coasting uphill with friction. The skier's mass is 71.8 kg, and they start with an initial speed of 8.84 m/s, coasting up a 25.1° slope for 2.10 m, ultimately reaching a speed of 3.41 m/s. The work done by the kinetic frictional force is calculated to be -1761 J. Participants seek clarification on how to determine the magnitude of the kinetic frictional force, with references to the definitions of work done and energy conservation. The conversation emphasizes the relationship between kinetic energy, potential energy, and the work-energy principle.
pvwill18
Messages
2
Reaction score
0
A 71.8-kg skier coasts up a snow-covered hill that makes an angle of 25.1 ° with the horizontal. The initial speed of the skier is 8.84 m/s. After coasting a distance of 2.10 m up the slope, the speed of the skier is 3.41 m/s. (a) Find the work done by the kinetic frictional force that acts on the skis. (b) What is the magnitude of the kinetic frictional force?

Part a= -1761 J

I Just can't figure out how to find part b
 
Physics news on Phys.org
What is the definition of work done?
 
Work done is equal to KE+PE so kinetic energy final + mgh- kinetic energy intial+ mgh where kinetic energy is 1/2mvsquared
 
There is another definition of work done which says
W=r \cdot F

Try it now.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top