Physics question - Constant acceleration and distance travelled

AI Thread Summary
The discussion centers on calculating the ratio of distances traveled by an object under constant acceleration over two time intervals. The question asks for the ratio D/d, where d is the distance traveled in the first 2 seconds and D in the next 2 seconds. Participants suggest using kinematic equations to derive the relationship between distance, velocity, and acceleration. A specific focus is on the equation for position over time, emphasizing the use of a velocity-time diagram to understand the areas representing distance. The conversation highlights the need to clarify the question and apply the correct formulas for a solution.
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physics question -- Constant acceleration and distance travelled

an object is moving with a constant acceleration, if it travels a distance d during the first 2 seconds and an additional D in the next 2 seconds the ratio of D/d is?

a) 1
b) 2
c) 3
d) 4

i don't understand exactly what the question is asking me to do?
 
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physics.geeks said:
an object is moving with a constant acceleration, if it travels a distance d during the first 2 seconds and an additional D in the next 2 seconds the ratio of D/d is?

a) 1
b) 2
c) 3
d) 4

i don't understand exactly what the question is asking me to do?

Welcome to the PF.

What is the equation that relates the distance traveled to the velocity and acceleration of an object? It is one of the basic kinematic equations for problems involving constant acceleration.

Write out that equation, and the answer should be pretty straightforward...
 


vf^2-Vi^2=2adeltax is the equation you're talking about? i tried rearranging that for x and have no clue where to go from there
 


berkeman said:
Welcome to the PF.

What is the equation that relates the distance traveled to the velocity and acceleration of an object? It is one of the basic kinematic equations for problems involving constant acceleration.

Write out that equation, and the answer should be pretty straightforward...

vf^2-Vi^2=2adeltax is the equation you're talking about? i tried rearranging that for x and have no clue where to go from there
 


physics.geeks said:
vf^2-Vi^2=2adeltax is the equation you're talking about? i tried rearranging that for x and have no clue where to go from there

No, I'm referring to the equation for x(t) in terms of initial position, initial velocity, acceleration, and time...
 


Use area of a triangles and square in a velocity-time diagram.
You can find v1, 2 and acceleration from this constant acceleration diagram.
Since it is a ratio you can start for v0=0.
 

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