Physics question on absolute pressure?

AI Thread Summary
To calculate absolute pressure from a gauge reading of -295 mmHg, atmospheric pressure of 101.7 kN/m^2, and vapor pressure of 2.8 kN/m^2, the correct approach involves understanding the relationship between these pressures. The gauge pressure is converted to 39.36 kN/m^2, and the equation p_gauge = p_absolute - atmospheric pressure is applied. The discussion highlights the importance of factoring in vapor pressure, which contributes to the total atmospheric pressure. The final calculation proposed by one participant, adding gauge pressure to atmospheric pressure and subtracting vapor pressure, yields a result of 59.34 kN/m^2. The conversation emphasizes the need for clarity on whether the vapor pressure refers to water vapor or another substance, as this affects the overall pressure calculation.
delfinofrank
Messages
4
Reaction score
0
Hey, here's the question:

"If a gauge reads -295mmHg where athmospheric pressure is 101.7 kn/m^2 and the vapor pressure is 2.8 kN/m^2, what is the absolute pressure?"

I converted the gauge pressure to 39.36 kN/m^2 but where do i go from here? I know the equation is p_gauge= p_absolute - atmospheric, but where do I factor in the vapor pressure?!

Please help! Thank you :)
 
Physics news on Phys.org
The water vapor pressure in the atmsosphere contributes to its atmospheric pressure. So if the atmospheric and gauge pressures are given, the absolute pressure is__________??
 
Are you sure it's water vapor pressure or could it be the vapor pressure of the mercury?
 
What I did was I added the gauge pressure and the athmospheric pressure and then subtracted the vapor pressure to get 59.34 kN/m^3. is that right?
 
When a pressure reading is given in mmHg, it is just an alternative unit of pressure which can be (like you did) converted to paschals or atmospehres, etc. In the US, atmospheric pressure is usually expressed in inches of Hg, or millibars, and there is no mercury in the air (or at leasts not much)!

I interpret vapor pressure as water vapor pressure in the atmosphere, although there are other vapors present, like oxygen and nitrogen, the sum total of which contributes to the atmospheric pressure. Thus, I do not agree with your answer.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top