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Physics question tension!

  • Thread starter terryW16
  • Start date
  • #1
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Homework Statement



A 2.0 X 10^-4 kg spider is suspended from a thin strand of spider web. The greatest tension the strand can withstand is 2.0 X 10^-3 N. if the spider was to ascend the strand from rest going to 1.0 m/s in 4.0 s with a steady acceleration, will the strand be able to support the motion?

Homework Equations





The Attempt at a Solution



2.0 X 10^-4 kg (9.8 m/s²) = 1.96 X 10^-3 kg(m)/s²

2.0 X 10^-4 kg (0.25 m/s²) = 5.0 X 10^-5

1.96 X 10^-3 + 5.0 X 10^-5 = 2.46 X 10^-4
yes because 2.0 X 10^-3 is greater than 2.46 X 10^-4
 

Answers and Replies

  • #2
Delphi51
Homework Helper
3,407
10
1.96 X 10^-3 + 5.0 X 10^-5 = 2.46 X 10^-4
Something has gone wrong here. Better run it through again.
It looks like your approach is correct, though difficult to follow.
Maybe better to write
F = ma
T - mg = ma
T = ma + mg = m(a+g), then put in the numbers.
This way, there is only one calc, half the chance of killing it with a typo!
 

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