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##\pi \rightarrow \gamma \gamma## spin,C,P

  1. Jun 12, 2015 #1


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    I was just wondering... Is it possible to explain the J,C,P of the [itex]\pi^0[/itex], [itex]J^{CP}=0^{+-}[/itex] just from the diphoton decay?
    [itex] \pi^0 \rightarrow \gamma \gamma[/itex]

    The [itex]C[/itex] is straightforward.
    However are the [itex]J,P[/itex] deduced by this interaction alone?
  2. jcsd
  3. Jun 12, 2015 #2

    Vanadium 50

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    No, because you can have any spin-even particle decay to two photons.
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