Pilots, diving and apparent weight

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Homework Help Overview

The discussion revolves around the concept of apparent weight experienced by a pilot while pulling out of a dive. Participants explore the physics behind forces acting on the pilot during upward acceleration and how this affects their perceived weight.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants attempt to relate their personal experiences in planes to the physics of apparent weight. Questions arise regarding the forces acting on the pilot and the distinction between weight and apparent weight during acceleration.

Discussion Status

The discussion is active, with participants exploring different interpretations of how upward acceleration affects apparent weight. Some guidance has been offered regarding the nature of forces and the mechanics of apparent weight, but no consensus has been reached on the implications of these concepts.

Contextual Notes

There is a focus on the distinction between upward acceleration and height, with some participants questioning the assumptions made about the relationship between these factors and apparent weight. The conversation includes references to specific scenarios, such as the operation of scales in a lift, to illustrate points being made.

NA19
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Homework Statement


While pulling out of a dive, does a pilot's apparent weight increase or decrease?


Homework Equations





The Attempt at a Solution


My instinct for this question says increase but only because of the feeling that I remember from being in planes. I'm trying to grasp the physics-based/conceptual explanation but don't really get it too much. And I'm not sure what equations would be relevant. I only understand apparent weight in the context of buoyancy...
 
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NA19 said:

Homework Statement


While pulling out of a dive, does a pilot's apparent weight increase or decrease?

You can think of apparent weight here as being equal§ to the force that the pilot's seat must exert on him to cause his body to follow the same trajectory as his plane.

§ equal but opposite to
 
Or, to make it easier, you can assume that the pilot is standing on a weighing machine inside the plane. When the pilot is moving upwards, what are the forces acting on him?
 
So wouldn't that just be the normal force which is equal to mg? Mathematically, it seems that his weight would decrease because gravity is acting on him pulling him downwards (mg) and the plane is pulling him up faster than gravity is pulling him down (mg + x). So his apparent weight would be mg - mg+x, like in hydrostatics...
 
Assume that pulling out of a dive means accelerating upwards.
 
So if you're accelerating upwards, wouldn't your apparent weight be less?
 
NA19 said:
the plane is pulling him up...

No, the plane is not pulling him up. It's pushing him up by the seat of his pants. Unlike gravity the planes upward acceleration does not act uniformly on his whole body.

When you sit in a chair you don't feel gravity pulling you down, you feel the reaction force from the chair pushing you up.

Perhaps consider how spring scales work.. There are two plates with a spring between them. A scale displays the amount that the spring is compressed. It doesn't matter if the top plate (with pilot on) is accelerated downwards by gravity or if the bottom plate is accelerated upwards by the plane. Both cause the spring to be compressed.
 
So, as anything increases in height above the ground, its apparent weight increases? For example, if I lifted an 8 pound weight, it would feel like it was heavier the higher I lifted it?
 
No it's not (necessarily) "increasing height" it's accelerating upwards.

It's possible for something to accelerate in one direction while still traveling in the other.

For example consider a car traveling at 50mph. It slams on the brakes and decelerates. Deceleration in the forward direction is the same as acceleration in the backward direction. In both cases the driver is thrown forwards in the seat right?

The plane is initially in a dive so it has velocity downwards. To pull out it has to first reduce it's vertical velocity to zero =deceleration = acceleration upwards.

At some point it's vertical velocity will reduce to zero and it will start to climb again but as soon as it starts to decelerate it's actually accelerating upwards.

It's the upward acceleration that makes the pilot feel heavier.
 
Last edited:
  • #10
NA19 said:
So, as anything increases in height above the ground, its apparent weight increases?
Definitely not.

For example, if I lifted an 8 pound weight, it would feel like it was heavier the higher I lifted it?
No. But if you replace the word "higher" with "more energetically" you would be spot on. (We are not talking about velocity, as such. The appropriate physics concept here is acceleration, and that's concerned with the changing of velocity.)
 
  • #11
NA19 said:
So, as anything increases in height above the ground, its apparent weight increases? For example, if I lifted an 8 pound weight, it would feel like it was heavier the higher I lifted it?

I suggest you take a set of bathroom scales to a lift in a tall building.

Enter the lift at the ground floor and press, say, levels 7, 14 and 20.

Now watch the the reading on the scales as you complete your journey up the level 20.

Once there, press ground, 8 and 15 and watch the scales during the return trip.

The scales will at all times be showing your apparent weight (which will be your actual weight at most times in those trips above - but will increase and decrease at various times).
 

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