Pipes and resonant mode with a node in exact center

AI Thread Summary
A pipe that can never have a resonant mode with a node in the exact center is one that is closed on both ends. This is because sound waves cannot escape, causing them to reflect back and forth without creating a node at the center. In contrast, an open pipe allows sound waves to pass through, preventing the necessary conditions for resonance. The discussion highlights that resonance requires specific boundary conditions, which are not met in a closed pipe scenario. Therefore, the conclusion is that a closed pipe cannot support a resonant mode with a node at the center.
oregongirl
Messages
1
Reaction score
0

Homework Statement


What kind of pipe can never have a resonant mode with a node in the exact center? (choices are closed on both ends, open/closed on one end only. open on both ends) why?


Homework Equations


none given


The Attempt at a Solution


I think its closed on both ends because there is no where for the sound to escape, it keeps going back and forth threw the tube, but I am not sure.
 
Physics news on Phys.org
I'd go with the one open on both ends. In order to achieve resonance you need a bouncing surface. In the open pipe, the perturbation will pass right through and there won't be any waves colliding and interfering, hence, no resonance.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How does water affect resonance in organ pipes?
Replies
10
Views
2K
Musical resonance of a cylinder/tube with a hole in the center
Replies
4
Views
2K
Difference between pressure antinodes and displacement node?
Replies
1
Views
3K
Waves in a closed organ pipe (homework check)
Replies
3
Views
3K
Tuning fork standing wave in a water pipe
Replies
2
Views
5K
Excitation of TEM mode through a slot
Replies
15
Views
2K
Why Does Covering One End of a Pipe Change the Pitch of the Sound Produced?
Replies
3
Views
2K
Speed of Sound in Air & Resonance in a Pipe
Replies
3
Views
3K
To find out mode of vibration of air in a resonating pipe
Replies
6
Views
3K
Resonant Lengths in open air column question
Replies
6
Views
3K

Hot Threads

Recent Insights

Back
Top