Pivoting Cylinder Homework: Find Angular Acceleration

[gonzalo12345]

Homework Statement

M, a solid cylinder (M=1.63 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder with a mass m = 0.830 kg is hung from the string, find the angular acceleration of the cylinder.

http://lc2.mines.edu/res/msu/physicslib/msuphysicslib/20_Rot2_E_Trq_Accel/graphics/prob16b_002masspulley2.gif

Homework Equations

torque = I(alpaha)

The Attempt at a Solution

I tried to solve the problem algebraically, and got (2mR)/(MR^2 - 2mR^2) but I keep getting it wrong.

 

[tiny-tim]

I tried to solve the problem algebraically, and got (2mR)/(MR^2 - 2mR^2) but I keep getting it wrong.

Show us what you tried, and then we'll be able to see where the mistake was.

 

[baba89]

I would like to provide a response to the homework problem. Firstly, it is important to note that the given information is not sufficient to solve the problem as it does not mention the force applied to the string or the moment of inertia of the cylinder.

However, assuming that the force applied to the string is known and the moment of inertia of the cylinder can be calculated, the angular acceleration can be found using the equation torque = moment of inertia * angular acceleration.

To calculate the moment of inertia of the cylinder, we can use the formula for a solid cylinder rotating about its central axis, which is I = (1/2)*M*R^2, where M is the mass of the cylinder and R is its radius.

Once the moment of inertia is known, the equation can be rearranged to solve for the angular acceleration, which would be alpha = torque / I.

In conclusion, to find the angular acceleration of the cylinder, we need to know the force applied to the string and the moment of inertia of the cylinder. Without this information, it is not possible to accurately solve the problem.