Please help explaining equation of the plane from the book.

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This is from "Field and Wave Electromagnetics" by Cheng. I don't understand how this work:

Let

\vec k \;=\; \hat x k_x + \hat y k_y + \hat z k_z \;\hbox { and }\; \vec R \;=\; \hat x x + \hat y y + \hat z z

be position vectors.

Find the equation of the plane perpendicular to \vec k and contain the tip of vector \vec k

ie: plane contain point P(k_x, k_y, k_z)




Let k^2 = k_x ^2 + k_y ^2 + k_z ^2.

The book said

\hat k \cdot \vec R = \hbox { constant }\;. is the equation of the plane!

Using the book’s formula and call the constant as A:

\hat k \cdot \vec R \;=\; \frac { \hat x k_x + \hat y k_y + \hat z k_z }{ k} \cdot (\hat x x + \hat y y + \hat z z) = \frac { x k_x + y k_y + z k_z }{k} = A

\Rightarrow \; x k_x + y k_y + z k_z \;=\; kA (1) is equation of plane.






Normal way of finding equation of plane using point normal is

\vec k \cdot (\vec R - \vec k )=0

\vec k \cdot (\vec R - \vec k ) \;=\; (\hat x k_x + \hat y k_y + \hat z k_z ) \cdot [(\hat x x + \hat y y + \hat z z)\;-\; (\hat x k_x + \hat y k_y + \hat z k_z )]

\Rightarrow\; x k_x + y k_y + z k_z = k^2 (2)




As you can see (1) is not the same as (2)

Can anyone explain to me?
 
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hi yungman! :smile:

the plane has to "contain the tip of vector k" …

ie R = k must work …

so the constant A in the equation k.R = A must be equal to k.k, ie k2

so (1) and (2) are the same, with A = k2 :wink:
 
Thanks Tiny-Tim.
 

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