Plotting & Verifying Air Pressure Reduction over Time

Click For Summary
SUMMARY

The discussion focuses on modeling air pressure reduction in a tank using the formula p=100(0.85)^t, where the air pressure decreases by 15% per second. Participants are tasked with plotting this function for the interval 0 < t < 30 seconds and determining the rate of change at t=5 seconds and t=10 seconds. The derivative p'(t)=dp/dt is utilized to find the rates of change at these specific time points, providing a straightforward method for verification through calculus.

PREREQUISITES
  • Understanding of exponential decay functions
  • Familiarity with calculus, specifically derivatives
  • Ability to plot graphs using mathematical software or tools
  • Knowledge of the concept of rate of change
NEXT STEPS
  • Learn how to differentiate exponential functions
  • Explore graphing tools such as Desmos or GeoGebra for visualizing functions
  • Study applications of calculus in real-world scenarios, particularly in physics
  • Investigate the implications of exponential decay in various scientific fields
USEFUL FOR

Students studying calculus, physics enthusiasts, engineers working with pressure systems, and anyone interested in mathematical modeling of decay processes.

hbuk
Messages
2
Reaction score
0
I am trying to complete the following question:

By pumping the air pressure in a tank is reduced by 15%/second. The percentage of air pressure remaining is fiven by the formula.

p=100(0.85)^t

Plot p against t for 0 < t < 30s.

Deternine the rate of change at 5s & 10s. I have plotted the graph.

Verify you anser via calculus.

Can anyone please advise which formula is applicable to this?
 
Physics news on Phys.org
hbuk said:
I am trying to complete the following question:

By pumping the air pressure in a tank is reduced by 15%/second. The percentage of air pressure remaining is fiven by the formula.

p=100(0.85)^t

Plot p against t for 0 < t < 30s.

Deternine the rate of change at 5s & 10s. I have plotted the graph.

Verify you anser via calculus.

Can anyone please advise which formula is applicable to this?

The rate of change is given by the derivative p'(t)=dp/dt where t is the argument(given in seconds). Your are interested in the rate of change at after 5s and 10s, hence you want to calculate p'(5) and p'(10).

You have plotted the graph so you could also find the slope of the tangent(2 lines) at t=5 and at t=10. But the first method is much easier if you know how to differentiate that function.
 
thank you, that makes sense.
 

Similar threads

Replies
8
Views
1K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
4
Views
2K
  • · Replies 45 ·
2
Replies
45
Views
6K
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 67 ·
3
Replies
67
Views
5K
  • · Replies 27 ·
Replies
27
Views
6K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K