Pn junction diode (series combo of voltage source and diode)

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SUMMARY

The discussion centers on calculating the current through a resistor in a circuit involving a pn junction diode and a voltage source. The user correctly applies Ohm's Law (V=IR) to determine the current, arriving at a value of 66 microamps (μA) by using the equation I=(0.8V - 0.7V)/1500Ω. The conversation highlights the importance of understanding the polarity of the voltage source in relation to the diode's forward voltage drop.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of pn junction diode characteristics
  • Familiarity with voltage sources and their polarity
  • Basic circuit analysis skills
NEXT STEPS
  • Learn about the characteristics of pn junction diodes
  • Study the metric prefix system for electrical measurements
  • Explore advanced circuit analysis techniques
  • Investigate the impact of resistor values on current flow in circuits
USEFUL FOR

Students studying electronics, electrical engineers, and anyone interested in understanding the behavior of circuits involving pn junction diodes and resistors.

NolcPhysics
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The question is to solve the current through a resistor after a pn junction. (photo attached)
As far as I'm aware the voltage source in the pn junction is (in this orientation) of opposite polarity to that of the 0.8V voltage source.

From my understanding the answer goes like:

V=IR
I=V/R

I=(0.8-0.7)/1500
I= 66e-6 Amps

I'm just checking my logic, I can't find anything in my lecture notes.
Chances are I'm wrong, circuits are the bane of my life so if anyone has any tips/advice on this I'd really appreciate it.
Thanks for reading!
IMAG0137[1].jpg
 
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Hi NolcPhysics, Welcome to Physics Forums.

In future please be sure to retain and use the posting template provided for formatting your question layout when you start a new thread in the Homework sections of the forums.

Regarding your problem, your method and results look fine. You might take advantage of the metric prefix system and choose a suitable unit size to display your result (micro amps, μA, would be appropriate).
 
ok, thanks.
I will in future
grand so, I wasn't sure if my logic was correct. I wasn't aware the prefix system here, now know about it.
 

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