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NolcPhysics

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The question is to solve the current through a resistor after a pn junction. (photo attached)

As far as I'm aware the voltage source in the pn junction is (in this orientation) of opposite polarity to that of the 0.8V voltage source.

From my understanding the answer goes like:

V=IR

I=V/R

I=(0.8-0.7)/1500

I= 66e-6 Amps

I'm just checking my logic, I cant find anything in my lecture notes.

Chances are I'm wrong, circuits are the bane of my life so if anyone has any tips/advice on this I'd really appreciate it.

Thanks for reading!