Point charges arranged as a trianngle

AI Thread Summary
The discussion revolves around calculating the electric force components acting on charge qC in an equilateral triangle configuration. The user attempts to find the y-component of the force, initially calculating it as 4.453e-1 N but believes this is incorrect. They correctly note that the x-components cancel out, leaving only the y-component to consider. Other participants point out errors in the user's calculations, particularly in the use of the distance and the formula for force. The thread highlights the importance of careful unit conversion and correct application of the formula for electric force.
jenzao
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Homework Statement


Consider three charges at the vertices of an equilateral triangle of side a = 7 cm. qA = +2 µC, qB = +2 µC, and qC = -1 µC. (see attached picture)

Find the x- and y- components of the electric force acting on qC



Homework Equations


i am doing everything right, but getting wrong answer ?


The Attempt at a Solution


x-comp cancel obviously, so I am left with finding y-comp...

F = kqAqC/r^2
= 2.571e-1

sin60(2.571e-1) = 2.2266e-1
multiply by 2 = 4.453e-1 N (this is wrong though)

i can't see the prob. The forces both point in positive y direction, so the y vectors sum
please help, thanks!
 

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jenzao said:

The Attempt at a Solution


x-comp cancel obviously, so I am left with finding y-comp...

F = kqAqC/r^2
= 2.571e-1

sin60(2.571e-1) = 2.2266e-1
multiply by 2 = 4.453e-1 N (this is wrong though)
=k.qA.qC/r^2
=9E9 x 2E-6 x 1E-6/0.07^2
=3.67

I see you are dividing by 7
Two mistakes it's 7cm and then its r^2
 
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