Points where tangent line touches 2 circles

madgab89
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Homework Statement


On the circles y^2+x^2=1 and y^2+(x-3)^2=4
There is a line with positive slope that is tangent to both circles. Determine the points at which this tangent touches each circle.

Homework Equations


the derivative of the first circle i found:
y'=-x/y

the derivative of the second cirlce I found:
y'=-2x+6/2y

and also
x^2+y^2=1


The Attempt at a Solution



so I have these equations for slopes:
-x1/y1

-2x2+6/2y2

y2-y1/x2-x1

Now where do I go from here, can someone get me started with the rearranging or whatever?
 
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What I think you should do is put the tangent as y=mx+c, then solve this with y^2+x^2=1, and when you simplify it into the form ax^2+bx+c=0, b^2-4ac=0 since it is a tangent. Then do the same with y^2+(x-3)^2=4 and you will get two equations in m and c.
 
madgab89 said:

Homework Statement


On the circles y^2+x^2=1 and y^2+(x-3)^2=4
There is a line with positive slope that is tangent to both circles. Determine the points at which this tangent touches each circle.

Homework Equations


the derivative of the first circle i found:
y'=-x/y

the derivative of the second cirlce I found:
y'=-2x+6/2y

and also
x^2+y^2=1

The Attempt at a Solution



so I have these equations for slopes:
-x1/y1

-2x2+6/2y2

y2-y1/x2-x1

Now where do I go from here, can someone get me started with the rearranging or whatever?

I think the main problem is that you haven't written down any equations yet. Those are expressions, not equations. Put in some equal signs. Do you want to say that all of those are equal to the unknown slope m?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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