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Pole Splitting equation question

  1. Nov 5, 2009 #1
    I'm trying to follow along with the equations on the wikiepdia page for pole splitting: http://en.wikipedia.org/wiki/Pole_splitting. However, I'm having a bit of trouble understanding the equation about halfway down that relates the load output to the amplifier input, Vl/Vi. Where does the zero in the numerator in the transfer function come from, that term divided by the amplifier gain? I thought the transfer function for the output network would be essentially identical to that of the input network, just with Cc in parallel with Cl. Thanks for any insight.
     
  2. jcsd
  3. Nov 21, 2009 #2

    The Electrician

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    Send me a PM with a valid email address, and I'll send you some material from old journals and magazines on the topic.
     
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