Position of Block After Applied Force of 2.8N

AI Thread Summary
The discussion revolves around calculating the position of a block attached to a spring on a frictionless surface after a force of 2.8 N is applied. The spring constant is given as 35 N/m, and the block initially at rest is pulled until it stops. Participants emphasize that at the stopping point, the applied force equals the spring force, suggesting a need to check the sign in calculations. There is a recommendation to post in the homework help section for further assistance. The main issue highlighted is the misunderstanding of directionality in the problem.
mochabcha
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I have a problem I need help with:
A block lies on a horizontal frictionless surface and is attached to the free end of the spring, with a spring constant of 35 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 2.8 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops.
Assume that the stopping point is reached. What is the position of the block?
 
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What's the problem with the problem ? Draw a force diagram. You know how to calculate the force due a stretched spring...do it.
 
I've tried the formula F(spring) = -kx and got -.08 but that's not the answer.

It seems to me when the mass stops the applied force will equal the spring force
 
next time try posting in the homework help section
 
And check your sign. Read what the question says about which direction (positive or negative x-direction) the block is pulled.
 

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