Position Vector & Displacement: Particle Homework

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The discussion centers on calculating the position vector and displacement of a watermelon seed with given coordinates. The position vector's magnitude is determined to be 11.9 meters, and the angle relative to the positive x-axis is found to be 133 degrees. For displacement, the magnitude is calculated as 15.2 meters, but there is confusion regarding the angle. The angle is derived from the displacement vector's components, leading to a calculation of -37.67 degrees, which is then debated in terms of how to express it relative to the positive x-axis. The conversation concludes with frustration over the automated grading system used for the homework, suggesting the need for instructor intervention.
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Homework Statement


A watermelon seed has the following coordinates: x = -8.1 m, y = 8.8 m, and z = 0 m. Find its position vector as (a) a magnitude and (b) an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (3.3 m, 0 m, 0 m), what is its displacement as (c) a magnitude and (d) an angle relative to the positive direction of the x axis?


Homework Equations





The Attempt at a Solution


a= 11.9 Meters
b= 133 degrees
c= 15.2 Meters
d = ?

How do I find this final angle??
 
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Find the x and y components of the displacement vector and get the angle the usual way.
 
All I have is the magnitude of the displacement vector. I know I need to find the x and y components of it, but how do I do that without at least having one of the angles? Or do i already have it??
 
You have the coordinates of two points. The displacement is a vector whose components is the difference finish - start, (x2-x1, y2-y1, z2-z1)
 
so my displacement vector's components are (11.4, -8.8, 0)? So the angle would be inverse tan of (-8.8/11.4)?
 
Correct.
 
the angle I get from that calculation is -37.67..Now it says it wants an angle relative to the positive direction of the x-axis. Would that be it, or do I have to subtract that number from something else?
 
Draw the point on a sheet of paper. Connect it with a straight line to the origin. Then look at the angle that starts on the positive x-axis and goes counterclockwise to the line that you have drawn. That's the one you want. What is its relation to 37.67 degrees?
 
ok, is it 360-37.67? which is going to be 322.33
 
  • #10
I put in 322.33, and it came out wrong! The correct angle was -37.67..Bummer
 
  • #11
Bummer indeed. If this is one of those evil Web-based, calculated type questions like Webassign or Mastering Physics, I think you should explain your answer to your instructor. Chances are he/she will override the machine. I know I would. :wink:
 
  • #12
yea wiley plus..Horrible system!
 
  • #13
thanks anyways for your help!
 
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