Positronium allowed decays (Peskin)

  • Thread starter Thread starter Hao
  • Start date Start date
  • Tags Tags
    Peskin
Hao
Messages
93
Reaction score
0

Homework Statement


(This is not homework)
This refers to question 3.8 in Peskin's QFT

Using the fact that the electromagnetic interaction term in the Dirac + EM lagrangian is invariant under Parity (P) and Charge conjugation (C), and that spin 0 and spin 1 states are odd and even under exchange of spins,

show that the
1) spin 0 positronium ground state (S wavefunction) decays into 2 photons, and that the
2) spin 1 positronium ground state (S wavefunction) must decay into 3 photons
3) The above for P, D states.


Homework Equations



EM coupling
\Delta H=\int A_{\mu}j^{\mu}d^{3}x

We know that under parity, j^{\mu}\rightarrow (j^{0},-j^{1},-j^{2},-j^{3})
We know that under parity, j^{\mu}\rightarrow -j^{\mu}

The Attempt at a Solution



By handwaving, we can say that these transitions occur due to conservation of angular momentum as a photon has a spin of 1.

However, how would these transitions be derived on the basis of C and P symmetries alone?

One could probably consider the interaction matrix term:

\left\langle photons\right|\Delta H\left|positronium\right\rangle

And determine how it transforms under C and P

The problem I have is in evaluating the P and C eigenvalues of states that contain only photons.

For a state involving a fermion and antifermion (eg. positronium), and with orbital angular momentum L, P|state> = (-1)L+1|state>. The extra factor of +1 is due to the anticommutativity of spin 1/2 creation operators.

Thanks
 
Physics news on Phys.org
For those who are interested, I've found a solution by somebody else.

http://www.maths.tcd.ie/~powersr/New/
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Back
Top