Positronium is an atom formed by an electron and a positron. It is similar to the
hydrogen atom, with the positron replacing the proton. If a positronium atom
makes a transition from the state n = 3 to a state with n = 1, the energy of the
photon emitted in this transition is closest to
The Attempt at a Solution
what will my proton number Z be in this case?
E = -13.6eV x Z2 / n2
but a hydrogen atom's Z = 1, what about the positronium atom? 0?
state n=3 has -1.511 eV while state 1 has -13.6 eV.
but the answer is 6 eV? how is that obtained? i have no idea . thanks for help!