(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Positronium is an atom formed by an electron and a positron. It is similar to the

hydrogen atom, with the positron replacing the proton. If a positronium atom

makes a transition from the state n = 3 to a state with n = 1, the energy of the

photon emitted in this transition is closest to

3. The attempt at a solution

what will my proton number Z be in this case?

E = -13.6eV x Z^{2}/ n^{2}

but a hydrogen atom's Z = 1, what about the positronium atom? 0?

state n=3 has -1.511 eV while state 1 has -13.6 eV.

but the answer is 6 eV? how is that obtained? i have no idea . thanks for help!

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# Homework Help: Positronium atom transition - energy of photon

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