- #1
Jude075
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Homework Statement
A rectangle has its base on the x-axis and its vertices on the positive portion of the parabola
$$ y=2-3x^2 $$
What is the maximum possible area of this rectangle?
A. (8/27)*181/2 B.(2/9)*181/2 C. (4/15)*301/2 D.(2/15)*301/2 E.(1/3)*121/2
Homework Equations
The Attempt at a Solution
The definite integral (or the area underneath the curve) from 2/3 to-2/3, which are the x-intercepts, is 56/27 .Since the rectangle is inside the parabola, I just need to find the number that is the closest. It is choice C, but the answer turns out to be A.
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