Potential Difference Across an Inductor in an RLC circuit

AI Thread Summary
In a series RLC circuit driven by an alternating source with an emf amplitude of 6.0V and a phase angle of +30 degrees, the maximum potential difference across the capacitor is +5.00V. The phase angle indicates that the voltage leads the current by 30 degrees, which is crucial for calculating the potential difference across the inductor. The relationship between the inductor's voltage (VL) and current (IL) is defined by the equation VL = IL * XL. The phase angle also relates to the complex impedance, where (XL - Xc)/R = tan(30°). Understanding these relationships is essential for determining the potential difference across the inductor in this scenario.
Senrab
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Homework Statement


An alternating source drives a series RLC circuit with an emf amplitude of 6.0V, at a phase angle of +30deg. When the potential difference across the capacitor reaches its maximum positive value of +5.00V, what is the potential difference across the inductor?


Homework Equations


Vc=IcXc, VL=ILXL


The Attempt at a Solution


I don't know because I don't know what to do with the phase angle.
 
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The phase angle of 30° means that the voltage leads the current by that angle. That is also the phase of the complex impedance: (XL-Xc)/R = tan(30°)

ehild
 

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