Potential difference and charge across a capacitor

AI Thread Summary
The discussion focuses on calculating the potential difference and charge across capacitors in a circuit. The 6μF, 4μF, and 8μF capacitors are identified as being in parallel, while the 9μF, 9μF, and 7μF capacitors are shorted out and can be disregarded. The equivalent capacitance of the 6μF, 4μF, and 8μF capacitors is in series with a 36μF capacitor. The potential difference across the 8μF capacitor is calculated to be 80/3 volts, resulting in a charge of 640/3 μC. The final answer is confirmed as correct.
Jahnavi
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Homework Statement


capacitor.PNG


Homework Equations

The Attempt at a Solution



Apologies for the question image not being very clear . I will refer capacitors by numerical value of their capacitance .

The 6 , 4 , 8 capacitors are in parallel .

9 , 9 , 7 are shorted out .So , we can remove them from the circuit .

So , effectively , the equivalent of 6,4,8 is in series with the 36 capacitor .

One end of 6,4,8 is at 40 Volts .Other end I calculated to be at 40/3 volts.

From this I get potential difference across 8μf capacitor to be 80/3 volts and charge 640/3 μC .

I get Option 3) .

Is this correct ?
 

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Yes.
 
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cnh1995 said:
Yes.

Thanks !
 
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