Potential difference in parallel circuit

AI Thread Summary
In a parallel circuit, the potential difference (P.D.) across each component is equal to the P.D. of the battery, meaning if a 12V battery is used, each component experiences 12V. This can be confusing because it seems like adding the voltages would exceed the battery's voltage; however, this is a misunderstanding of how voltage works in parallel circuits. The potential difference across ideal conductors is zero, which means all points connected by these conductors share the same voltage. Therefore, the P.D. across each component remains consistent with the battery's voltage, regardless of the number of components. Understanding this principle clarifies why the total voltage does not add up in the way one might initially expect.
Johnahh
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Homework Statement


I am currently revising some AS level Circuit modules and I'm having trouble seeing how the P.D across 3 components in a parallel circuit can each have the same value as the P.D of the battery.
I am probably just being dumb but its just not making sense!
such as this:
http://physicsnet.co.uk/wp-content/u...l-circuits.jpg
 
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I'm unable to access your problem. The link, when clicked, leads to a page which says Error 404:Page not found.
 
Johnahh said:
http://physicsnet.co.uk/a-level-physics-as-a2/current-electricity/circuits/ - right at the bottom
basically if you have a 12v supply with 3 components how can the PD across each component be 12 when 3x12 = 36v?

I'm sure you know that potential difference across an ideal conducting wire is always zero right?(Because no work is needed to be done by the electric field to move charges across it)

Now check out the attachment. (in the first figure) ABCD is an ideal conductor and so is PQRS. So potential difference across AB, BC and CD is zero right? Similarly across PQ, QR, RS.

So whatever was the potential at A will be the potential at B, C and D. Similarly, whatever was the potential at P will be the potential at Q, R and S.

Thus the potential difference across AP, BQ, CR and DS should be the same right?

So you can simply do away with all those excess connections and simply connect all the resistors across AP right? (Like in the second figure)

(In your question, when you added the voltages, you are siply adding thevoltages across the same two points)
 

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