Potential difference of concentric conducting shells

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Two concentric conducting spherical shells with charges +q and -q require the use of Gauss's Law to determine the electric field and potential difference between them. To find the potential difference V_{a}-V_{b}, one must integrate the electric field from the inner shell to the outer shell. The charge Q in Gauss's Law refers to the enclosed charge within the chosen Gaussian surface, which should be located in the region where the electric field is being analyzed. The integration can be performed from either a to b or b to a, as the sign of the result will simply indicate the direction of potential difference. Understanding these concepts is crucial for accurately calculating the potential difference between the shells.
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Two concentric conducting spherical shells have equal and opposite charges. The inner shell has outer radius a and charge +q; the outer shell has inner radius b and charge -q. Find the potential difference V_{a}-V_{b} between the shells

My professor said to in order to solve this, integrate the electric field to find the electric potential...

\Delta V = -\int\stackrel{\rightarrow}{E}dl

My question is, using Gauss's Law, (\oint E_{n}dA = \frac{Q}{\epsilon}), how do I go about finding Q?

Isn't Q just the charge of the shell?
 
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In Gauss's law, Q is the charge enclosed by your Gaussian surface. So, first decide where you Gaussian surface will be, then add up all the charge inside of it.

HINT: You want your surface to be in the region where you want to find the electric field.
 
G01 said:
In Gauss's law, Q is the charge enclosed by your Gaussian surface. So, first decide where you Gaussian surface will be, then add up all the charge inside of it.

HINT: You want your surface to be in the region where you want to find the electric field.

This is what I have drawn (see attachment). Is the basic idea here to integrate the electric field of the outer Gaussian surface from b to a? If so, what about the inner Gaussian surface?
 

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You want to find the potential difference between the shells, so you don't need the Gaussian surface outside the larger shell.

Try this: Take your inner surface and place it at an arbitrary point r. Then, find E using the standard approach when using Gauss's law. You will then have E between the plates as a function of r. Can you use that to find the potential difference between the plates?
 
G01 said:
You want to find the potential difference between the shells, so you don't need the Gaussian surface outside the larger shell.

Try this: Take your inner surface and place it at an arbitrary point r. Then, find E using the standard approach when using Gauss's law. You will then have E between the plates as a function of r. Can you use that to find the potential difference between the plates?

Alright... see attached image.

Now, how do i determine if i should integrate from a to b or from b to a?
 

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faint545 said:
Alright... see attached image.

Now, how do i determine if i should integrate from a to b or from b to a?

That all looks good.

As far as your integration bounds are concerned, it doesn't matter. The sign of your end result will change, but that's just like hooking up a voltmeter in reverse: You will still get the right pot. difference, just the sign will change.
 
thanks for your guidance
 
faint545 said:
thanks for your guidance

No problem! :smile:
 
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