Potential difference question - Immediate

AI Thread Summary
The discussion revolves around calculating the current through a battery when the terminal voltage Vba is -40V. The key equation used is VT = emf - iR, where the terminal voltage is linked to the external voltage and internal resistance. There is confusion regarding the application of terminal voltage and the direction of current flow, with clarification needed on voltage conventions. It is established that Vba represents the voltage of b relative to a, and that the correct interpretation leads to understanding the current direction and magnitude. The final conclusion is that the current is 8.0A, flowing from point a to b in the circuit.
MathewsMD
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The emf and internal resistance are shows in the attached image. When the terminal voltage, Vba, is equal to -40V, what is the current through the battery, including its direction?

Solution:

VT = emf - iR (general)

In this case, VT = 40V, when considering VT = Vab = Vb - Va

VT = Vext - 28V - i(1.5Ω)

Now, I'm not entirely certain of where I went wrong, but don't seem to know much about the current besides that it is going from a to b in the cell.

The solution shows the answer is 8.0A but I can only get that if I do 0 = 40V - 28V - i(1.5Ω) but I don't quite see how you can apply the 40V inside (using Kirchoff's loop rule) if that's the terminal voltage instead of the applied voltage from an external source. Any clarification on what I am doing wrong or what I should do, and clarification on VT would be helpful.

This is what I quickly used as a reference: http://www.physics.ucla.edu/demoweb...d_magnetism/dc_circuits/terminal_voltage.html
 

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Vba : is A positive compared to B, or vice-versa?
 
rude man said:
Vba : is A positive compared to B, or vice-versa?

All I'm given is what I have given you. Since Vba = -40V, Vab = 40V and I was under the impression then that b is the + side and a is -. Am I mistaken?

Also, when they say current goes from a to b, do they mean in the cell itself or outside? If it is outside, then this makes sense and I think they are trying to say then that it is a that is + and b that is -. But any explanation for how one would come to that conclusion simply given everything I have given you would be great! Thanks!
 
Vab = Vb - Va

Not correct.
VT = Vext - 28V - i(1.5Ω)

This doesn't look right.

EDIT
You'll find it easier if you picture b as 0v, and making every other point positive wrt end b.

The voltage between b and a is the terminal voltage.
 
Last edited:
NascentOxygen said:
Not correct.




This doesn't look right.

EDIT
You'll find it easier if you picture b as 0v, and making every other point positive wrt end b.

The voltage between b and a is the terminal voltage.

Oh, so Vba = Va - Vb? If so, that's where I went wrong. I just don't know why I've haven't up on this convention...
 
MathewsMD said:
Oh, so Vba = Va - Vb?
No.

Vba is read as "the voltage of b wrt a".
 
Imagine charging a 28 V battery using a 40 V source.
If Vba = - 40 V, Vab is 40 V. 28 of those are over the battery, the remainder over the 1.5 Ω. There is only 1 current and it's going all round.
 
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