Potential Energy: Hiker at 1600m to 3100m - Change, Work, & Explanation

AI Thread Summary
The discussion focuses on the potential energy change for a 55-kg hiker ascending from 1600 m to 3100 m. The change in potential energy is calculated using the formula mgh, where m is mass, g is gravitational acceleration, and h is the height difference. The minimum work required is equivalent to the change in potential energy, but actual work done may exceed this due to factors like friction and drag. The aerodynamic drag at low speeds, specifically between 1 to 3 miles per hour, is also questioned, indicating its relevance to the overall work done by the hiker. Understanding these concepts is crucial for accurately assessing the energy dynamics involved in hiking at significant elevations.
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A 55-kg hiker starts at an elvation of 1600 m and climbs to the top of a 3100-m peak. (a) What is the hiker's change in potential energy? (b) What is the minimum work required of the hiker? (c) Can the actual work done be more than this? Explain
 
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i know how to do part a, but can you by any chance help me with my problem, its titeled LOOP problem with DIAGRAM!
 
a) mgh= mgh
55(9.81)(1600)=(55)(9.81)(h)

you just solve for height by the equation above.
 
> Can the actual work done be more than this?

What's the aerodynamic drag at 1 to 3 miles per hour?
 
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