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Homework Statement
Two point charges of magnitude 4.79 nC and
−1.11 nC are separated by 39.4 cm.
The acceleration of gravity is 9.8 m/s^2
The Coulomb constant is 8.98755×10^9
N · m^2 /C^2.
What is the potential energy of the pair of
charges?
Answer in units of V.
Homework Equations
Voltage = Potential energy / charge
Voltage = (k*q)/(r)
r being the distance
k being Coulomb's constant
and q being the charge of the point charge
Coulomb's constant: 8.98755E9
The Attempt at a Solution
So I think the problem wants me to find the voltage of the system judging by the "Answer in units of V. So I solved each charge for the voltage then added them together:
Vq1 = (k * 4.79e-9) / (39.4/100) = 109.264884518V
Vq2 = (k * 1.11e-9) / (39.4/100) = 25.3202550761V
So the sum of the two (Vq1 + Vq2) would be the total potential energy of the pair of charges in unit V which equals: 134.585139594V, which is wrong.
I believe I may be reading the question wrong possibly, or just using the wrong method.