A force of 790 N stretches a certain spring a distance of 0.135 m. What is the potential energy of the spring when a mass of 62.0 hangs vertically from it?(adsbygoogle = window.adsbygoogle || []).push({});

I thought starting with finding the spring constant k would be good and i got it to be 585.85. i then plugged it into the potential energy equation u= .5(k)(x)^2 where x is the displacement. I got the new displacement by setting up a porportional equation and the new x was .104 m.

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# Homework Help: Potential energy of a spring

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