Potential energy of an object with initial velocity.

AI Thread Summary
The discussion centers on the calculation of kinetic, potential, and mechanical energy for a .300-kg ball thrown vertically upward with an initial speed of 10.0 m/s. The initial potential energy is considered zero based on the problem's parameters, which raises questions about the relationship between initial velocity and potential energy. The confusion arises from the understanding that while the ball has an initial velocity, potential energy can still be defined as zero at the chosen reference point, such as the height at which it is released. The key takeaway is that potential energy is dependent on the chosen reference height, which can be set to zero at the point of release. This clarification emphasizes the importance of defining the reference point in energy calculations.
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Homework Statement


A .300-kg ball is thrown vertically upward with an initial speed of 10.0 m/s. If the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energy at it's initial position.


Homework Equations


1/2mv(f)^2 + mgy(f) = 1/2 mv(i)^2 + mgy(i)


The Attempt at a Solution



I understand how to solve the problem. From my equation I've plugged in the 10 m/s for the inital and zero for the potential. Is potential energy zero because the book said it was? What I don't understand is why potential energy is zero when initial velocity is 10 m/s. If there is initial velocity shouldn't there be a numerical quality in the y direction? To be more clear, if an object is initially moving at a certain rate, shouldn't the ball have left the person's hand and given the ball some sort of height even a little bit?
 
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PE = mgy = 0 when y = 0 and the thing is, you can define y to be zero wherever you like. Sea level? Ground level? In this case, the height where it leaves the hand and when t = 0.
 
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