Potential energy of an object with initial velocity.

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SUMMARY

The discussion centers on calculating the kinetic, potential, and mechanical energy of a .300-kg ball thrown vertically upward with an initial speed of 10.0 m/s. The initial potential energy is defined as zero, which is a standard convention in physics when measuring from a reference point. The confusion arises from the relationship between initial velocity and potential energy, as potential energy is dependent on height, not velocity. The equation used is 1/2mv(f)^2 + mgy(f) = 1/2 mv(i)^2 + mgy(i), where the initial height is set to zero.

PREREQUISITES
  • Understanding of kinetic energy (KE = 1/2 mv^2)
  • Knowledge of potential energy (PE = mgy)
  • Familiarity with the conservation of mechanical energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Review the concept of reference points in potential energy calculations
  • Explore the conservation of mechanical energy in vertical motion
  • Learn about the effects of initial velocity on energy calculations
  • Investigate different scenarios for defining zero potential energy
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation principles, as well as educators seeking to clarify concepts related to potential and kinetic energy.

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Homework Statement


A .300-kg ball is thrown vertically upward with an initial speed of 10.0 m/s. If the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energy at it's initial position.


Homework Equations


1/2mv(f)^2 + mgy(f) = 1/2 mv(i)^2 + mgy(i)


The Attempt at a Solution



I understand how to solve the problem. From my equation I've plugged in the 10 m/s for the inital and zero for the potential. Is potential energy zero because the book said it was? What I don't understand is why potential energy is zero when initial velocity is 10 m/s. If there is initial velocity shouldn't there be a numerical quality in the y direction? To be more clear, if an object is initially moving at a certain rate, shouldn't the ball have left the person's hand and given the ball some sort of height even a little bit?
 
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PE = mgy = 0 when y = 0 and the thing is, you can define y to be zero wherever you like. Sea level? Ground level? In this case, the height where it leaves the hand and when t = 0.
 

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