Potential Energy Q: 1000kg Cart on Hill, Kinetic/PE/Velocity?

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A 1000kg cart starts at the top of an 80m hill with a potential energy of 800,000J and zero kinetic energy. As it rolls down to a smaller hill, it reaches a velocity of 20m/s, resulting in a kinetic energy of 200,000J. The conservation of energy principle indicates that the total mechanical energy remains constant, allowing for the calculation of the height of the smaller hill. By applying the formula mgh1 = mgh2 + 1/2mv^2, the unknown height (h2) can be determined through algebraic manipulation. This approach effectively illustrates the relationship between potential and kinetic energy in the context of gravitational forces.
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Question: There is a 1000kg cart on the top of 80m hill which it rolls down onto a smaller hill of unknown height with a velocity of 20m/s. What is potential energy and height of its current position? What is the kinetic energy, potential energy, and velocity when it reaches a flat surface? Assume no losses to friction and with a g of 10m/s. Thanks a lot
 
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So far I have the four answers for when they are at the top of the 80m hill before moving. K.E.=0 P.E.= 800000J, V=0, H=80m. I've calculated their kinetic energy to be 200000J at the smaller hill with the information provided(v=20m/s) I would appreciate it if someone could tell me how to go about doing this question.
 
energy is conserved So

(top) mgh1 = mgh2 + 1/2mv^2 (smaller hill)

you know everything but "h2", use algebra to find "h2"
 
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