Potential & Kinetic Energy Calc: x0=3.2m to x1=2.8m | Help Needed

AI Thread Summary
The discussion focuses on calculating the change in potential and kinetic energy for a particle influenced by a conservative force defined by F=(-Ax+Bx^2)iN, with A=48N/m and B=93N/m^2. The user initially believed the change in potential energy was zero and calculated the kinetic energy as -277.696 J, which was incorrect. Another participant suggested using the integral method to find the change in potential energy, leading to a successful resolution of the problem. The user expressed gratitude for the assistance received.
Xamfy19
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i need help for this problem.

A single conservative force acting on a particle varies as:

F=(-Ax+Bx^2)iN

where A=48N/m and B=93N/m^2 and x is in meters.
Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J.
Find the change in kinetic energy of the particle between the same two points. Answer in units of J.

I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.
 
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Try this:
\Delta U = -\int_{x_o}^{x_f} F(x)\cdot dx
 
Last edited:
Thanks alot

It worked. Thanks.
 
cool thanks :)
 
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