Potential for two semicircular rods

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The discussion focuses on calculating the electric potential at point P, located between two semicircular rods with different radii, R1 and R2. The potential is influenced by the charge per unit length, lambda, on the rods. There is a question about whether the electric fields from the two horizontal rods cancel each other out, leading to the conclusion that only the inner rod's field needs to be considered. The proposed formula for the electric field at point P is 2k(lambda)*(1/R1 + 1/R2). The inquiry also includes whether the integral for potential should extend from 0 to R1.
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Homework Statement


Two semicircular rods, one of radius R1 and the other of radius R2 where R2 > R1, are joined by two horizontal, straight rods. The rods carry a charge of lambda coulombs per meter. Calculate the potential at point p at the center of the two semicircles. (P would be the center of the two concentric circles if the rods were full circles)

This configuration looks like a rainbow basically and p is on the ground halfway between each side of the rainbow.


Homework Equations


V= KQ/R
V= E*s

The Attempt at a Solution



If I calculate V using the electric field, does the electric field between the two rods cancel so I would just have to use the electric field due to the inner rod? I know the electric fields of the two horizontal rods cancel.
 
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OK I suppose my real question is, is the electric field at point P

2k(lambda)*(1/R1 + 1/R2)

And then if that is so, to find the potential does the integral go from 0 to R1?
 

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