Potential Function from a simple conservative force

AI Thread Summary
The discussion focuses on finding potential functions for two conservative forces, F=xi+yj and F=yi+xj. The initial approach involves integrating the force to obtain the potential energy, which works for the first equation but leads to an incorrect result for the second. A participant clarifies that the correct method involves calculating the work done along specific paths, confirming that the work is independent of the path taken. The correct potential function for the second force is identified as -xy+C, resolving the confusion. The thread concludes with an acknowledgment of the solution provided.
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Homework Statement


Find the potential functions for these conservative forces:

(1)F=xi+yj

(2)F=yi+xj

Homework Equations


F=-\nablaV (Force = -del (Pot.energy))


The Attempt at a Solution



So, I'm guessing to get V I just need to integrate F. For the first equation that gets me the right answer hurray!

However I think my method is wrong(or my general understanding the opposite of partial derivatives). Doing the same thing to eqn 2 leaves me with a slight problem.
-(\inty dx +\intx dy)leaves me with -2xy+C. The correct answer should be -xy+C

(I checked and it is indeed a conservative force)

Please enlighten me
Thanks in advance
 
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For a conservative force, the work between two points is independent on the connecting path. Start to integrate from point (0,0) to point P(X,Y).
You can follow the line along the x-axis from x=0 to x=X and then a straigth line parallel to the y-axis from (X,0) to (X,Y). The work done is

V(0,0)-V(X,Y)=\int_{(0,0)}^{(X,Y)}{ydx+xdy}=\int_{(0,0)}^{(0,X)}{ydx}+\int_{(X,0)}^{(X,Y)}{xdy}

As y=0 along the first line, and x=X along the second one, the first integral is 0, the second one is XY.

ehild
 
solved. thanks
 
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