Potential of Ag/Ag+ electrode

  • Thread starter Chris-jap
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  • #1
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Hello everybody

I would like to know the potential of two electrode.

1- The first is the electrode of Ag/Ag+ in a saturated solution of NaCl

I think that the pKs of AgCL is 9.8 (is it right?)
So
E= E0+0.06log[(Ks)1/2]
E=0.8-0.506
E=0.506 vs ENH

Is it correct? (in a book I found a value of 0.2 so...)

2- The second is the electrode of Ag/Ag+ in a solution of NaCl at 3 mol/L this time
so
E=E0+0.06logKs-0.06log[Cl+] ??
E=0.8-0.588-0.0286=0.183 V vs ENH
Is it correct?

Thank you for your help
Chris
 

Answers and Replies

  • #2
siddharth
Homework Helper
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Chris-jap said:
Hello everybody

I would like to know the potential of two electrode.

1- The first is the electrode of Ag/Ag+ in a saturated solution of NaCl

I think that the pKs of AgCL is 9.8 (is it right?)
So
E= E0+0.06log[(Ks)1/2]
E=0.8-0.506
E=0.506 vs ENH

Is it correct? (in a book I found a value of 0.2 so...)
The Ksp is 1.8*10^-10, so the pKs comes to around 9.745.

Everything seems right, till "E=0.8-0.506". Shouldn't it be 0.588, as you used in the next question? If you do that, you get E = 0.8-0.588
= 0.212

2- The second is the electrode of Ag/Ag+ in a solution of NaCl at 3 mol/L this time
so
E=E0+0.06logKs-0.06log[Cl+] ??
E=0.8-0.588-0.0286=0.183 V vs ENH
Is it correct?
This appears correct (ofcourse, Cl-).
 

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