Power dissipation in capacitor circuit

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Discussion Overview

The discussion revolves around the calculation of power dissipation in a capacitor circuit connected to a battery with internal resistance. Participants explore whether to consider only the heat dissipated by the capacitor or to include the heat lost in the battery due to its internal resistance.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions if the power dissipated as heat can be calculated solely by multiplying the voltage across the capacitor by the current through it, or if it is necessary to include the heat dissipated in the battery due to its internal resistance.
  • Another participant asserts that the capacitor absorbs some energy from the battery, and only the energy lost in the internal resistance is converted to heat.
  • A third participant agrees with the previous point but notes that a textbook answer only considers heat dissipation in the capacitor, suggesting that the dissipation in the battery may have been overlooked.
  • One participant challenges the notion of current "through" the capacitor, clarifying that current flows through the connecting wires and the battery during charging, but not through the capacitor itself.

Areas of Agreement / Disagreement

Participants express differing views on whether to include the heat dissipation in the battery when calculating total power dissipation, indicating that the discussion remains unresolved.

Contextual Notes

There are assumptions regarding the definitions of current flow in the circuit and the treatment of energy dissipation in both the capacitor and the battery that remain unaddressed.

apkrishna1963
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Capacitor connected to a battery of certain internal resistance. If it is asked to calculate what is power dissipated as heat, Does -the voltage across capacitor X current through capacitor- gives heat dissipated or should we add heat dissipated in battery by considering its internal resistance.
 
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The capacitor will take some part of the energy released by the battery, only the fraction that is lost in the internal resistance gets converted to heat.
 
@mfb, I agree. But in the book the answer given for only heat dissipation in capacitor. They have not considered the dissipation in battery. I think they have neglected this fraction of heat lost. But strictly speaking one has to consider. Am I right?
mfb said:
The capacitor will take some part of the energy released by the battery, only the fraction that is lost in the internal resistance gets converted to heat.
 
apkrishna1963 said:
Capacitor connected to a battery of certain internal resistance. If it is asked to calculate what is power dissipated as heat, Does -the voltage across capacitor X current through capacitor- gives heat dissipated or should we add heat dissipated in battery by considering its internal resistance.
What current "through" capacitor? The current goes through the connecting wires and through the battery, during the charging process. But not through the capacitor.
Maybe you should write the full text of the problem.
 
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