Think Kirchoff's laws, you can use these the calculate the voltage or current at each point in the circuit.MD2000 said:
The power dissipation in a resistor can be calculated using the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance. In this case, if the voltage across the resistor is known, the power can be calculated by simply plugging in the value of 6.0 ohms for R.
The voltage across a resistor can be calculated using Ohm's law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance. In this case, if the current through the resistor is known, the voltage can be calculated by plugging in the value of 6.0 ohms for R.
This depends on the power rating of the resistor. The power rating is the maximum amount of power that a resistor can safely handle without overheating or getting damaged. To determine if a 6.0 ohm resistor can handle high power, you will need to know its power rating. If the power dissipation in the resistor exceeds its power rating, then it may not be able to handle high power.
The power dissipation in a resistor is directly proportional to its resistance. This means that if the resistance of the resistor is doubled, the power dissipation will also double. Similarly, if the resistance is halved, the power dissipation will also be halved. However, keep in mind that the power dissipation also depends on the voltage across the resistor, so changing the voltage will also affect the power.
Connecting two resistors in parallel effectively decreases the resistance of the circuit. This means that the power dissipation will increase, as more current will flow through the circuit. However, the power dissipation in each individual resistor will remain the same, as it is determined by the voltage and resistance of each resistor individually. It is important to make sure that the power rating of each resistor is high enough to handle the increased power dissipation in a parallel circuit.