Power Needed to Accelerate 1200 kg Car from Rest to 20 m/s

AI Thread Summary
To determine the average power needed for a 1200 kg car to accelerate from rest to 20 m/s in 6 seconds, the kinetic energy formula is applied, resulting in 240,000 J of work done. This work is calculated by recognizing that the energy imparted to the car translates into kinetic energy. Dividing the work (240,000 J) by the time (6 seconds) yields an average power output of 40,000 Watts, or 40 kW. This confirms that the correct answer is option D. The discussion emphasizes the importance of understanding the relationship between work, energy, and power in physics.
wolves5
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A car with a mass of 1200 kg accelerates from rest to 20 m/s in 6.0 seconds. What average power must the car produce to cause this acceleration?

a. 5 kW
b. 15 kW
c. 30 kW
d. 40 kW

For this problem, I did (1200)(9.81) and got the force. Then I used d= (6 seconds) x ((0 +20)/2) to find the distance. I got 60 meters as my distance. I then did force times distance to get the Work. Then I divided the Work by 6 seconds because that's how you get power. I got an answer that was none of the options above. What am I doing wrong?
 
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The weight of the car is not the force doing the acceleration (unless of course it's fallen off a cliff!).

The work done while accelerating the car goes into giving it kinetic energy, expressed as velocity. If you know the velocity at the end of 6.0 seconds you should be able to calculate the work done; what's the kinetic energy for mass 1200kg moving with velocity 20 m/s?
 
The kinetic energy is 240000 J.
 
Do you divide 240,000 by 6 seconds? I got 40,000 Watts when I did that which is 40 kW. So is it D?
 
wolves5 said:
Do you divide 240,000 by 6 seconds? I got 40,000 Watts when I did that which is 40 kW. So is it D?

You've already stated that average power is given by work done divided by the time over which it is done. So you should have confidence in your result.
 
So the kinetic energy or the 240,000 J was the Work?
 
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