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Power of a source

  1. May 29, 2006 #1
    Sir,
    A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
    I solved it in the following way:
    Intensity = power/Area
    Here Area = (pi)R^2
    = 3.14 x 0.01
    = 0.0314 m^2
    Power = 0.2 x 0.0314 milli watts
    = 6.28 x 10^(-6) watts
    Is it right?
     
  2. jcsd
  3. May 29, 2006 #2

    Chi Meson

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    Looks correct to me. Did you think it was too easy?
     
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