Power output/input, energy input, efficiency of engine & generator

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Homework Help Overview

The discussion revolves around the concepts of power output/input, energy input, and efficiency in the context of engines and generators. Participants are examining equations related to power, energy, and efficiency calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt various calculations using equations for power and efficiency, questioning the validity of their results. There are discussions about the small torque output of a diesel engine and the relationship between power input and output. Questions arise regarding the derived units for watts and the use of hours in calculations.

Discussion Status

Participants are actively engaging with the problem, sharing calculations and expressing uncertainty about their answers. Some guidance is offered regarding the relationship between power input and output, as well as clarifications on efficiency definitions. Multiple interpretations of efficiency and power calculations are being explored.

Contextual Notes

There is mention of missing information regarding fuel consumption, which affects the ability to estimate heat input. Participants are also navigating homework constraints and the definitions of units related to energy and power.

DevonZA
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Homework Statement


upload_2016-5-3_20-46-16.png


Homework Equations


P=2piNT/60
P=I^2R
Pin=Pout/efficieny
E=P/t

The Attempt at a Solution



2.1 P=I^2R
= (5)^2x48
= 1200W

2.2 Pin=Pout/efficiency
= 1200/0.86
= 1395.35W

2.3 P=2piNT/60
*3100.78=2pi(500)T/60
T=0.016Nm.

2.4 Total efficiency = (45/100x86/100)x100% = 38.7%

2.5 Pin=Pout/efficiency
= 1395.35/0.45
= 3100.78W*

2.6 E=P/t
= 3100.78/4x60x60
= 0.215J

2.7 3.1kWx4hoursxR4.75/kWh = R58.90

I don't feel satisfied that these answers are correct, probably because they are not.
The answer to 2.6 concerns me most.
When can I use the equations P=I^2R and E=I^Rt?
 
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DevonZA said:

Homework Statement


View attachment 100189

Homework Equations


P=2piNT/60
P=I^2R
Pin=Pout/efficieny
E=P/t

The Attempt at a Solution



2.1 P=I^2R
= (5)^2x48
= 1200W

2.2 Pin=Pout/efficiency
= 1200/0.86
= 1395.35W

2.3 P=2piNT/60
*3100.78=2pi(500)T/60
T=0.016Nm.
Extremely small torque output for a diesel engine. You would do much better turning a hand crank.

However, you overlooked the fact that the power output of the diesel engine = power input of the generator.

The efficiency for the diesel engine comes from how much energy in the fuel is converted to useful work at the shaft.
2.4 Total efficiency = (45/100x86/100)x100% = 38.7%

2.5 Pin=Pout/efficiency
= 1395.35/0.45
= 3100.78W*

2.6 E=P/t
= 3100.78/4x60x60
= 0.215J
What are the derived units for watts? Why have you used hours?
2.7 3.1kWx4hoursxR4.75/kWh = R58.90

I don't feel satisfied that these answers are correct, probably because they are not.
The answer to 2.6 concerns me most.
When can I use the equations P=I^2R and E=I^Rt?
 
SteamKing said:
Extremely small torque output for a diesel engine. You would do much better turning a hand crank.

However, you overlooked the fact that the power output of the diesel engine = power input of the generator.

The efficiency for the diesel engine comes from how much energy in the fuel is converted to useful work at the shaft.

What are the derived units for watts? Why have you used hours?

Hi Steamking

Power input of gen = 1395.35W = power output of engine

P=2pi(N)(T)/60
1395.35=2pi(500)T/60
T=1850.64Nm
That's better :)

The efficiency for the diesel engine comes from how much energy in the fuel is converted to useful work at the shaft.

I'm lost here. Isn't the efficiency the output power/input power x 100%?

Derived unit for watts..power? I have used hours because I need to calculate kw/h?
 
DevonZA said:
Hi Steamking

Power input of gen = 1395.35W = power output of engine

P=2pi(N)(T)/60
1395.35=2pi(500)T/60
T=1850.64Nm
That's better :)

The efficiency for the diesel engine comes from how much energy in the fuel is converted to useful work at the shaft.

I'm lost here. Isn't the efficiency the output power/input power x 100%?
You can only measure the output power of the diesel engine.

The amount of heat input theoretically furnished by the fuel can be estimated if you know the fuel consumption of the engine, which in this case you don't. :frown:

However, given the efficiency of the engine, you can work back and estimate how much fuel the engine burns in a given amount of time.
Derived unit for watts..power? I have used hours because I need to calculate kw/h?
Kilowatt-hours is a unit of energy, not kilowatts per hour. The definition of the watt is the same as it always was - the amount of work performed in joules per second.

https://en.wikipedia.org/wiki/Kilowatt_hour
 
I will look at this again in the morning, it is almost midnight here.
Thanks for your help.
 

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