Power over current source and resistor in series

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SUMMARY

The discussion focuses on calculating the output power (both P and Q) of a current source in a series circuit with a resistor, specifically addressing Kotitehtävä 7. The voltage across the resistor was calculated as 0.832∠-33.69° V. It was established that the voltage across the current source is equal to that across the resistor, as the current source has no impedance. The recommended approach to resolve the issue involves using nodal analysis to determine the voltage at the central node, which will subsequently allow for the calculation of the voltage across the current source.

PREREQUISITES
  • Understanding of series circuits and current sources
  • Knowledge of complex voltage representation (phasors)
  • Familiarity with nodal analysis techniques
  • Basic principles of electrical power calculations (P and Q)
NEXT STEPS
  • Study nodal analysis in electrical circuits
  • Learn about calculating power in AC circuits
  • Explore the concept of impedance in current sources
  • Review complex number operations in electrical engineering
USEFUL FOR

Electrical engineering students, circuit designers, and professionals involved in power analysis and circuit design will benefit from this discussion.

mkerikss
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Problem description:

The problem is Kotitehtävä 7 in the attachement. The idea is to calculate the output power (both P and Q) of the current source.

Attempt:

I know the current through the current source (obviously) and want to calculate the voltage over it to get the power. I have calculated the voltage over the RJC part of the circuit. It is 0,832\angle-33,69° V. The voltage over the resistor and current source is the same, but then I figured that all the voltage will be over the resistor, since the current source doesn't have any impedance. So now I'm stuck. How can I solve this problem?
 

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If you use nodal analysis to find the voltage at the central node, then you can find the voltage across the current source since the drop across the resistor is fixed by the current source.
 
Thanks, I'll try to do that!
 

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