Power PLEASE Help Test THURSDAY

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Power equations can yield different results due to the configuration of the circuit, especially when light bulbs are wired in series. In this case, using P = V^2/R is crucial for accurately calculating the power dissipated by each bulb. The total voltage is divided between the bulbs, leading to a reduced current and power output compared to their rated values. For two 97 W bulbs at 114 V in series, the correct power dissipation per bulb is 24.3 W, not simply 97 W each. Understanding the relationship between voltage, current, and resistance is essential for solving these types of problems accurately.
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Power...PLEASE Help...Test THURSDAY!

I am having a hard time understanding why some power equations for finding the power dissipated by light bulb(s) don't work. I have...
P = IV = I^2R = V^2/R
But for some of the problems these equations are getting me different numbers for each one! I am getting confused and I now don't know when to use which one and I have a test on Thursday! One example...

Two 97 W (114 V) lightbulbs are wired in series, then the combination is connected to a 114 V supply. How much power is dissipated by each bulb?

I found I using P/V = .851 then when I go to find the power the only equation that gets me the right answer is P = V^2/R then divide by 2 = 24.3 W
 
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The current reduces through each when connected in series, so that the power is not just 2*97 W. You have to find the V across each or find I.
 
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