Power required to move up an incline

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To determine the power required for a car to ascend a 10% grade at 60 km/h, the mass of the car is 1800 kg, and the gravitational acceleration is 9.81 m/s². The normal force was calculated as approximately 1755.25 N, but the frictional force remains unknown, complicating the calculation. The discussion suggests considering the force of gravity acting along the incline to find the required force to overcome it. The velocity of the car is converted to 16.667 m/s, leading to a focus on calculating work done per second. The solution emphasizes using work, power, and motion formulas to find the necessary power without delving into energy concepts yet.
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Homework Statement



What power is needed to drive a car at 60 km/h up a 10% grade.

mass=1800kg
v=60km/h
theta=5.7106
g= 9.81 m/s^2

Homework Equations



P = Fv
P_ave= W/T
w=mg
F=ma

The Attempt at a Solution



I drew my diagram and FBD.

Since Fy=mAy=0..

0=N-sin(5.7106)
N=1755.2477

I know that Ax will be 0 since the velocity is constant, and I need to find the frictional constant:

mAx=0=F-uk-mgcos(5.7106)

But I don't have F, since it's what I'm trying to find..and this is where I've been stuck.
 
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Maybe consider the rate of change of potential energy?
 
Problem with that is we haven't learned anything about energy yet so we are supposed to use regular Work, Power, and other Motion formulas.
 
Ut Prosim said:
Problem with that is we haven't learned anything about energy yet so we are supposed to use regular Work, Power, and other Motion formulas.

OK. So consider then the force of gravity along the incline.

The car travels at 16.667 m/s, so in 1 second, what force was required to overcome gravity over that distance?

That gives you W per sec = F*d per sec.
 
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