- #1

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[tex](2x+3)^3(x-4)[/tex]

How do I differentiate this?

How do I differentiate this?

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- #1

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[tex](2x+3)^3(x-4)[/tex]

How do I differentiate this?

How do I differentiate this?

- #2

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Use the product rule: [itex] vdu + udv [/itex]. For the first function use the power rule: [itex] x^n = nx^{n-1} \frac{du}{dx}=(3(2x+3)^2(2) [/itex]

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- #3

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Ok. Thanks!

- #4

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[tex]\frac{dy}{dx}=3(2x+3)^2(2) + 1[/tex]

Right?

Right?

- #5

arildno

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You must be more careful!

Define:

[tex]f(x)=(2x+3)^{3},g(x)=(x-4)[/tex]

Then,

[tex]y(x)=f(x)g(x),y'(x)=f'(x)g(x)+f(x)g'(x)[/tex]

You need therefore to calculate f'(x) and g'(x)

- #6

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I got it! Thank you!

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