Power series expansion of a function of x

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SUMMARY

The discussion focuses on the power series expansion of the function defined by the integral \(\int_0^x e^{-t^2} dt\). The participant successfully derives the series expansion as \(\sum_0^{\infty} \frac{(-1)^n(x^{2n+1})}{n!(2n+1)}\) and confirms its convergence for all real numbers \(x\) using the ratio test. It is established that integrating a power series term by term is permissible within the radius of convergence, affirming the validity of the approach taken.

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with the ratio test for series convergence
  • Knowledge of Taylor series expansions, particularly for \(e^{-t^2}\)
  • Basic calculus concepts, including integration of functions
NEXT STEPS
  • Study the properties of power series and their intervals of convergence
  • Learn about the application of the ratio test in determining series convergence
  • Explore the derivation and implications of Taylor series expansions
  • Investigate the integral of power series and conditions for term-by-term integration
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Students and educators in calculus, mathematicians interested in series expansions, and anyone looking to deepen their understanding of power series and their applications in mathematical analysis.

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Homework Statement



[Directions to problem]
Show that the function of x gives a power series expansion on some interval centered at the origin. Find the expansion and give its interval of validity.

[tex]\int_0^x e^{-t^2} dt[/tex]

Homework Equations





The Attempt at a Solution



I have that, [tex]e^{-t^2} = \sum_0^{\infty} \frac{(-1)^n(t^2)^n}{n!}[/tex]

I now am wondering whether I can take the integral of this series as follows,

[tex]\int_0^x \sum_0^{\infty} \frac{(-1)^n(t^2)^n}{n!} dt = \sum_0^{\infty} \frac{(-1)^n(x^{2n+1})}{n!(2n+1)}[/tex]

Am I allowed to do that and if so, what is the justication?

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I performed the ratio test on the result and the limit as n approached 0 was 0, and I therefore concluded that the series converges for all x in R.
 
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I think you mean "prove the function has a power series" since the integration itself does not directly "give" the power series.

Yes, as long as you are inside the radius of convergence, you can integrate a power series term by term.
 
Also the series expansion of [tex]e^{x}[/tex] is valid for all x
 

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